StackGeneric-and-Interfaces-Exceptions

Build on the examples given in 1009-classwork.zip.

1.

Explain why the following code will not compile:

import StackGeneric.*;_x000D_
_x000D_
public class Test0 {_x000D_
_x000D_
    public static void main(String [] args){_x000D_
        Stack<Integer> st = new Stack<Integer>();_x000D_
        for( int i = 0 ; i < 5 ; i++) {_x000D_
            st.push(i);_x000D_
        }_x000D_
        st.push(5);_x000D_
		System.out.println(st.pop());_x000D_
    }_x000D_
}_x000D_

2.

Explain why the following two examples throw an exception when run.

---

import StackGeneric.*;_x000D_
_x000D_
public class Test {_x000D_
_x000D_
    public static void main(String [] args){_x000D_
        Stack<Integer> st = new IntegerStackArray();_x000D_
        int n = st.pop();_x000D_
    }_x000D_
}_x000D_

---

import StackGeneric.*;_x000D_
_x000D_
public class Test2 {_x000D_
_x000D_
    public static void main(String [] args){_x000D_
        Stack<Integer> st = new IntegerStackArray();_x000D_
        for( int i = 0 ; i < 1000 ; i++) {_x000D_
            st.push(i);_x000D_
        }_x000D_
        st.push(5);_x000D_
    }_x000D_
}_x000D_

---

3.

Read the Java tutorial on Exceptions, up to and including the section on finally blocks.

4.

In Problem 2. above, both examples threw ArrayIndexOutOfBoundsException exceptions. Using the following template, modify the method

public void push(Integer value)

so that if pushing results in exceeding the maximum size of the array, the ArrayIndexOutOfBoundsException is caught, an appropriate message is printed, but the program continues, though the requested action is not completed.

Template:

try{ /* ... */ }_x000D_
catch(ArrayIndexOutOfBoundException e){ /* ... */ }_x000D_

5.

In the above example, I referred to the method “push” using the full signature. Why is this good practice, rather than just writing “push”?

6.

Complete the problem described in the picture slide 1(1009 Information) in the folder 10/09.

 

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